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fix:无限返回

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This commit is contained in:
loong 2021-10-28 10:15:19 +08:00
parent bd0b5edf68
commit d115651513
1 changed files with 10 additions and 7 deletions
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17
ReAiHuanYouJi.js
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@ -47,7 +47,7 @@ function start() {
} }
} }
} }
//任务类型二,累计浏览加购5个商品 // 任务类型二,累计浏览加购5个商品
else if (textContains("累计浏览").exists() && !isFinish("累计浏览")) { else if (textContains("累计浏览").exists() && !isFinish("累计浏览")) {
let win = textContains("累计浏览").findOnce().parent(); let win = textContains("累计浏览").findOnce().parent();
log(win.child(1).text()); log(win.child(1).text());
@ -60,16 +60,19 @@ function start() {
let inlineWin = textStartsWith("¥").findOnce().parent().parent(); let inlineWin = textStartsWith("¥").findOnce().parent().parent();
for (let i = Number(finishedTaskNum); i < Number(allTaskNum); i++) { for (let i = Number(finishedTaskNum); i < Number(allTaskNum); i++) {
log("浏览第" + (i + 1) + "个商品"); log("浏览第" + (i + 1) + "个商品");
log(inlineWin)
while (!inlineWin) {
back();
log("有意外弹窗,返回");
sleep(timeGap);
}
inlineWin.child(i).child(5).click(); inlineWin.child(i).child(5).click();
sleep(timeGap*2); sleep(timeGap*2);
back(); back();
sleep(timeGap); sleep(timeGap);
for(let i=0;!className("android.view.View").textContains("5个商品领汪汪币").findOnce()&&i<4;i++) {
if(i==3){
log("无法返回退出脚本,请重新执行脚本")
exit();
}
back();
log("无法返回加购页面,第"+(i+1)+"次返回(最多三次)");
sleep(timeGap);
}
} }
back();//返回任务界面 back();//返回任务界面
sleep(timeGap); sleep(timeGap);